How do you factor the expression #x^2+8x+15#?

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Answer 1 · 2016-01-02T17:09:16

#(x+3)(x+5)#

Find #2# integers whose sum is #8# and whose product is #15#.

These numbers are #3# and #5#, since

#3+5=8#
#3xx5=15#

Use the numbers #3# and #5# in two binomials, as follows:

#(x+3)(x+5)#

This is #x^2+8x+15# in factored form.

You can check your work by redistributing and seeing if you get #x^2+8x+15#.

#(x+3)(x+5)=x(x)+5x+3x+3(5)=x^2+8x+15#