# How do you factor the expression #x^3 + 3x^2 + 4x + 12#?

##### 2 Answers

#### Answer:

#### Explanation:

#color(blue)"factor by grouping"#

#=color(red)(x^2)(x+3)color(red)(+4)(x+3)#

#"take out the "color(blue)"common factor "(x+3)#

#=(x+3)(color(red)(x^2+4))#

#"we can factor "x^2+4" by solving "x^2+4=0#

#x^2+4=0rArrx^2=-4rArrx=+-2i#

#rArrx^2+4=(x+2i)(x-2i)#

#rArrx^3+3x^2+4x+12=(x+3)(x+2i)(x-2i)#

#### Answer:

#### Explanation:

If you are asked to completely factor an expression with four terms such as this, check to see if you are able to **FACTOR BY GROUPING** . If you can, this will be a simple process!

First, split the expression into two, find and factor out their greatest common factor in each term, and add them back together.

The common factor of the first half (

Now factor out and add back the expressions into:

This is not your final answer, however.

Note that the the two halves of the expression share a common factor, **FACTOR BY GROUPING** . You can factor out

Neither of these two terms can be factored no more. Therefore, this is your final answer!

**Remember that the presence of a common factor at the second step indicates that you may FACTOR BY GROUPING to easily answer this question.**