# How do you factor the following differences of two cubes 54x^3-16y^6?

$54 {x}^{3} - 16 {y}^{6} = 2 \left(27 {x}^{3} - 8 {y}^{6}\right) =$
$= 2 \left(3 x - 2 {y}^{2}\right) \left(9 {x}^{2} + 6 x {y}^{2} + 4 {y}^{4}\right)$.
${a}^{3} - {b}^{3} = \left(a - b\right) \left({a}^{2} + a b + {b}^{2}\right)$.