How do you factor the trinomial #10g^2+10=29g#?

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Answer 1 · 2016-01-30T17:25:38

This is an equation, and so I'll solve the equation for you.

#10g^2 + 10 = 29g#

#10g^2 - 29g + 10 = 0 #

When factoring trinomials of the form #ax^2 + bx + c#, where #a!=0,1#, you must find two trinomials that multiply to #a xx c# and that add to #b#

Two numbers that multiply to #100# and add to #- 29# are # - 25# and #- 4#

#10g^2 - 4g - 25g + 10 = 0#

#2g(5g - 2) - 5(5g - 2) = 0#

#(2g - 5)(5g - 2) = 0#

Set each of the individual parts equal to #0# and solve both of them.

#g = 5/2# and #2/5#

So, your solution set is #g = 5/2# and #2/5#