How do you factor the trinomial #14x^2 – 19x – 3#?

1 Answer
Shwetank Mauria
Sep 9, 2016

#14x^2-19x-3=(7x+1)(2x-3)#

Explanation:

To factorize #14x^2-19x-3#, we should split the coefficient of middle term #-19# in two parts whose product is product of coefficients of other two terms, i.e. #14xx(-3)=-42#.

The pair could be #+2# and #-21# and hence

#14x^2-19x-3#

= #14x^2-21x+2x-3#

= #7x(2x-3)+1(2x-3)#

= #(7x+1)(2x-3)#

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