Question

How do you factor the trinomial `d^2 + 15d + 44`?

Answer 1

`d^2+15d+44=(x+4)(x+11)`.

Explanation:

`d^2+15d+44`

Find two numbers that when added equal 15 and when multiplied equal 44. The numbers 4 and 11 meet the criteria.

Rewrite the trinomial as `(x+4)(x+11)`.

Answer 2

`(d+11)(d+4)`,
`d=-11`,
`d=-4`.

Explanation:

You multiply the constant multiplying `d`, which is `1`, times the last number, `44`. This gives us the value `44`. Now you look for factors of `44` that add up to `15`. These are `11` and `4`. So, we write them in the form `(d+a)(d+b)`, where `d` is `d`, `a` is the first factor, `11`, and `b` is the second factor, `4`. So,
`(d+11)(d+4) = 0`
`d=-11`,
`d=-4`.

Hope it Helps! :D .