How do you factor the trinomial #x^2 + 12x + 20#?

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Answer 1 · 2016-03-02T17:53:53

To factor a trinomial of the form of the form #y = ax^2 + bx + c#, we must find two numbers that multiply to c and that add to b.

Two numbers that multiply to 20 and that add to 12 are 10 and 2.

So, #(x + 10)(x + 2) is the proper factoring of that trinomial.

Practice exercises:

a) #x^2 + 8x + 9#

b) #x^2 - 8x - 9#

c) #x^2 + 8x - 9#

d) #x^2 - 8x + 9

e) #x^2 - 9x + 8#

f) #x^2 + 6x + 9#

g) #x^2 + 6x - 9#

h) #x^2 - 6x + 9#

g) #x^2 - 13x - 90#

Good luck!