How do you factor the trinomial #x^2 + 4x - 32 #?

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Answer 1 · 2015-12-30T19:57:56

You find its roots then write them in factor form, which means equaling each root to zero.

Solving using Bhaskara:

#(-4+-sqrt(4^2-4(1(-32))))/2#

#(-4+-sqrt(16+128))/2#

#(-4+-sqrt(144))/2#

#(-4+-12)/2#

#x_1=4 =># Factor form: #x-4=0#
#x_2=-8 =># Factor form: #x+8=0#

Thus, #x^2+4x-32=color(green)((x-4)(x+8))#