How do you factor the trinomial #x^2-6/5x+9/25#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Shwetank Mauria Jun 1, 2016 #x^2-6/5x+9/25=(x-3/5)^2# Explanation: As #9/25# is the square of #3/5# and middle term #6/5# is double of this number, (compare it with #(x-a)^2=x^2-2ax+a^2#) #x^2-6/5x+9/25# is a complete square. #x^2-6/5x+9/25# = #x^2-2xx3/5xx x+(3/5)^2# = #(x-3/5)^2# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1508 views around the world You can reuse this answer Creative Commons License