Question

How do you factor the trinomial `x^2+9x+8`?

Answer 1

Find two numbers that multiply to term c in `ax^2` + bx + c and that addd to term b

Explanation:

Two numbers that multiply to 8 and that add up to 9 are 8 and 1, so we have our factors

= (x + 1)(x + 8)

Answer 2

It is

`x^2+9x+8=x^2+x+8x+8=x^2+x+8*(x+1)=x*(x+1)+8*(x+1)=(x+8)*(x+1)`