How do you factor (x+1)^2-2(x+1)+1?

1 Answer
Sep 1, 2016

x xx x

Explanation:

This is a disguised quadratic: it is in the form ax^2 + bx +c

Except that instead of x, the 'variable' is (x+1)

Let (x+1) = b, so that the expression becomes b^2 - 2b +1

The factors of 1 which add to 2 are 1 and 1.
Both signs are negative.

(b-1)(b-1) " but " b= x+1

#(x+1-1)(x+1-1)

x xx x