# How do you factor (x+1)^2-2(x+1)+1?

Sep 1, 2016

$x \times x$

#### Explanation:

This is a disguised quadratic: it is in the form $a {x}^{2} + b x + c$

Except that instead of $x$, the 'variable' is $\left(x + 1\right)$

$L e t \left(x + 1\right) = b ,$ so that the expression becomes ${b}^{2} - 2 b + 1$

The factors of 1 which add to 2 are 1 and 1.
Both signs are negative.

$\left(b - 1\right) \left(b - 1\right) \text{ but } b = x + 1$

#(x+1-1)(x+1-1)

$x \times x$