# How do you factor (x-1)^2 (3x-1)-2(x-1)?

Jun 27, 2016

$\left(x - 1\right) \left(3 x + 2\right) \left(x - 2\right)$

#### Explanation:

There is a common bracket which can be taken out from each term.

$\left(x - 1\right) \left[\left(x - 1\right) \left(3 x - 1\right) - 2\right]$

Multiply the terms inside the bracket to see if they can be simplified and factorised further.

$\left(x - 1\right) \left(3 {x}^{2} - 4 x - 4\right]$

$\left(x - 1\right) \left(3 x + 2\right) \left(x - 2\right)$