How do you factor #(x-1)^3 - (x-1)^2 #? Algebra Polynomials and Factoring Factoring Completely 1 Answer ali ergin May 13, 2016 #"Factors :"(x-1)^2*(x-2)# Explanation: #(x-1)^3 -(x-1)^2# #(x-1)*(x-1)^2-(x-1)^2# #(x-1)^2[(x-1)-1]# #(x-1)^2*(x-2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 4816 views around the world You can reuse this answer Creative Commons License