How do you factor $x^2 +1 - x$ ?

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Answer 1 · 2015-06-07T14:19:33

$x^2+1-x = x^2-x+1$

is of the form $ax^2+bx+c$ with $a=1$ , $b=-1$ and $c=1$

The discriminant $Delta$ is given by the formula:

$Delta = b^2-4ac = (-1)^2-(4xx1xx4) = 1-4 = -3$

Since $Delta < 0$ the equation $x^2-x+1 = 0$ has no real roots and the quadratic $x^2-x+1$ has no linear factors with real coefficients.

How do you factor x^2 +1 - xx^2 +1 - x?