How do you factor #x^2 +1 - x#?

1 Answer
George C.
Jun 7, 2015

#x^2+1-x = x^2-x+1#

is of the form #ax^2+bx+c# with #a=1#, #b=-1# and #c=1#

The discriminant #Delta# is given by the formula:

#Delta = b^2-4ac = (-1)^2-(4xx1xx4) = 1-4 = -3#

Since #Delta < 0# the equation #x^2-x+1 = 0# has no real roots and the quadratic #x^2-x+1# has no linear factors with real coefficients.

Related questions
See all questions in Factoring Completely
Impact of this question
1140 views around the world
You can reuse this answer
Creative Commons License