How do you factor #x^2 +1 - x#?

1 Answer
George C.
Jun 7, 2015

#x^2+1-x = x^2-x+1#

is of the form #ax^2+bx+c# with #a=1#, #b=-1# and #c=1#

The discriminant #Delta# is given by the formula:

#Delta = b^2-4ac = (-1)^2-(4xx1xx4) = 1-4 = -3#

Since #Delta < 0# the equation #x^2-x+1 = 0# has no real roots and the quadratic #x^2-x+1# has no linear factors with real coefficients.

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