How do you factor $x^2+-16$ ?

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Answer 1 · 2015-07-06T19:22:19

$(x+4)(x-4) = x^2 - 16$

$(x+4i)(x-4i) = x^2 + 16$

$(x+y)(x-y) = x^2 - y^2$

$y = bi \Rightarrow (x+bi)(x-bi) = x^2 - (bi)^2 = x^2 + b^2$

How do you factor x^2+-16x^2+-16?