# How do you factor x^2+16x+64?

Feb 17, 2017

${x}^{2} + 16 x + 64 = {\left(x + 8\right)}^{2}$ is a perfect square trinomial.

#### Explanation:

Given:

${x}^{2} + 16 x + 64$

Note that both ${x}^{2}$ and $64 = {8}^{2}$ are both perfect squares, so we should check whether the middle term matches the middle term of ${\left(x + 8\right)}^{2}$...

${\left(x + 8\right)}^{2} = {x}^{2} + 2 \left(x\right) \left(8\right) + {8}^{2} = {x}^{2} + 16 x + 64$

So ${x}^{2} + 16 x + 64 = {\left(x + 8\right)}^{2}$ is a perfect square trinomial.