How do you factor $x^2+16x+64$ ?

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Answer 1 · 2017-02-17T00:12:05

$x^2+16x+64 = (x+8)^2$ is a perfect square trinomial.

Given:

$x^2+16x+64$

Note that both $x^2$ and $64=8^2$ are both perfect squares, so we should check whether the middle term matches the middle term of $(x+8)^2$ ...

$(x+8)^2 = x^2+2(x)(8)+8^2 = x^2+16x+64$

So $x^2+16x+64 = (x+8)^2$ is a perfect square trinomial.

How do you factor x^2+16x+64x^2+16x+64?