How do you factor #x^2+1x-12#?

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Answer 1 · 2016-12-19T14:52:14

#(x + 4)(x - 3)#

To solve this problem we must play with multipliers for 12 (1x12, 2x6 3x4) which also add to #1#:

#(x + 4)(x - 3)#

Answer 2 · 2016-12-19T14:53:09

#(x-3)(x+4)# is the answer

First, multiply #12# by the coefficient of the square, i.e

#12 * 1 = 12#

Now use two factors of #12# to get #1x# either by adding or by subtracting the factors.

#x^2 +x-12#

#=x^2-3x+4x-12#

#=x(x-3)+4(x-3)#

#=(x-3)(x+4)#