How do you factor $x^2 – 2/3 x + 1/9$ ?

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Answer 1 · 2016-04-25T15:40:34

$(x-1/3)(x-1/3) -> (x-1/3)^2$

Note that $1/3xx1/3=+1/9" and that "1/3+1/3=2/3$

Also $(-1/3)xx(-1/3) = +1/9$

$(x-1/3)(x-1/3) -> (x-1/3)^2$

How do you factor x^2 – 2/3 x + 1/9x^2 – 2/3 x + 1/9?