# How do you factor x^2 – 2/3 x + 1/9?

$\left(x - \frac{1}{3}\right) \left(x - \frac{1}{3}\right) \to {\left(x - \frac{1}{3}\right)}^{2}$
Note that $\frac{1}{3} \times \frac{1}{3} = + \frac{1}{9} \text{ and that } \frac{1}{3} + \frac{1}{3} = \frac{2}{3}$
Also $\left(- \frac{1}{3}\right) \times \left(- \frac{1}{3}\right) = + \frac{1}{9}$
$\left(x - \frac{1}{3}\right) \left(x - \frac{1}{3}\right) \to {\left(x - \frac{1}{3}\right)}^{2}$