How do you factor #x^2 – 2/3 x + 1/9#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Tony B Apr 25, 2016 #(x-1/3)(x-1/3) -> (x-1/3)^2# Explanation: Note that #1/3xx1/3=+1/9" and that "1/3+1/3=2/3# Also #(-1/3)xx(-1/3) = +1/9# #(x-1/3)(x-1/3) -> (x-1/3)^2# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1168 views around the world You can reuse this answer Creative Commons License