How do you factor #x^2(25 - x^2)- 4(25 - x^2)#? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. May 30, 2015 #x^2(25-x^2)-4(25-x^2)# #=(x^2-4)(25-x^2)# #=(x^2-2^2)(5^2-x^2)# #=(x-2)(x+2)(5-x)(5+x)# ...using the difference of squares identity: #a^2-b^2 = (a-b)(a+b)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1585 views around the world You can reuse this answer Creative Commons License