How do you factor $x^{2} + 3 x - 4$ $x^2+3x-4$ ?

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Answer 1 · 2018-05-11T22:40:29

Into two binomial ( x + 4) x ( x -1)

The equation in the $A x^{2} + B x + C$ $Ax^2 + Bx + C$

The C is negative which indicates that one binomial will be negative and one binomial will be positive.

The B is positive which indicates that the positive binomial will be larger than the negative binomial

The B is +3 which tells that the difference in the two factors is 3

so $(x + 4) \times (x - 1)$ $( x + 4) xx( x -1)$

How do you factor x^2+3x-4x2+3x−4x^2+3x-4?