# How do you factor x^2 - 4x - 12?

Mar 4, 2018

$\left(x - 6\right) \left(x + 2\right)$
$\text{consider the factors of - 12 which sum to - 4}$
$\text{these are - 6 and + 2}$
$\Rightarrow {x}^{2} - 4 x - 12 = \left(x - 6\right) \left(x + 2\right)$