How do you factor $x^2 - 4x - 12$ ?

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Answer 1 · 2018-03-04T09:22:15

$(x-6)(x+2)$

$"consider the factors of - 12 which sum to - 4"$

$"these are - 6 and + 2"$

$rArrx^2-4x-12=(x-6)(x+2)$

How do you factor x^2 - 4x - 12x^2 - 4x - 12?