How do you factor $x^2 - 7xb + 6b^2$ ?

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Answer 1 · 2015-06-08T06:48:13

Since all the terms are of order $2$ it's similar to factoring a quadratic in one variable $x^2-7x+6$ .

$x^2-7x+6=(x-1)(x-6)$

$1 + 6 = 7$ and $1 xx 6 = 6$

$x^2-7xb+6b^2 = (x-b)(x-6b)$

How do you factor x^2 - 7xb + 6b^2x^2 - 7xb + 6b^2?