Question

How do you factor `x^2 - 7xb + 6b^2`?

Answer 1

Since all the terms are of order `2` it's similar to factoring a quadratic in one variable `x^2-7x+6`.

`x^2-7x+6=(x-1)(x-6)`

`1 + 6 = 7` and `1 xx 6 = 6`

`x^2-7xb+6b^2 = (x-b)(x-6b)`