How do you factor #(x^2+8)^2-36x^2#?

1 Answer
Nov 5, 2015

Answer:

# (x^2+6x +8)(x^2-6x+8)#

Explanation:

As you can see, you have the difference of two squares: #(x^2+8)^2# is obviously the square of #(x^2+8)#, and #36x^2# is the square of #6x#.

A known formula states that the difference of squares is

#a^2-b^2=(a-b)(a+b)#

So, we have that

#(x^2+8)^2-36x^2 = (x^2+8 +6x)(x^2+8-6x)#