# How do you factor x^2-8x+16?

I would try to find two numbers that added together give $- 8$ and multiplied $16$: they can be: $- 4$ and $- 4$:
$\left(x - 4\right) \left(x - 4\right) = {\left(x - 4\right)}^{2} = {x}^{2} - 8 x + 16$