How do you factor $x^{2} - x - 72$ $x^2-x-72$ ?

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Answer 1 · 2018-03-24T11:33:09

$(x - 9) (x + 8)$ $(x-9)(x+8)$

$x^{2} - x - 72 = x^{2} - 9 x + 8 x - 72$ $x^2-x-72 = x^2-9x+8x -72$

$= x (x - 9) + 8 (x - 9) = (x - 9) (x + 8)$ $= x(x-9)+8(x -9)= (x-9)(x+8)$

$= (x - 9) (x + 8)$ $=(x-9)(x+8)$ [Ans]

How do you factor x2−x−72x^2-x-72?