Question

How do you factor `x^2-xy-56y^2`?

Answer 1

`x^2-xy-56y^2 = (x-8y)(x+7y)`

Explanation:

Find a pair of factors of `56` which differ by `1`.

The pair `8, 7` works in that `8xx7=56` and `8-7=1`

Hence:

`x^2-xy-56y^2 = (x-8y)(x+7y)`