How do you factor $x^{3} + 216$ $x^3 + 216$ ?

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Answer 1 · 2015-09-25T23:13:12

Refer to explanation

Using the identity $a^{3} + b^{3} = (a + b) \cdot (a^{2} - a b + b^{2})$ $a^3+b^3=(a+b)*(a^2-ab+b^2)$ and the fact that
$216 = 6^{3}$ $216=6^3$

we have that

$x^{3} + 6^{3} = (x + 6) \cdot (x^{2} - 6 x + 36)$ $x^3+6^3=(x+6)*(x^2-6x+36)$

How do you factor x^3 + 216x3+216x^3 + 216?