How do you factor $x^3+6x^2-x-30$ ?

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Answer 1 · 2018-03-14T13:53:22

$(x-2)(x+3)(x+5)$

$x^3+6x^2-x-30$

= $x^3-8+6x^2-24-(x-2)$

= $(x-2)(x^2+2x+4)+6(x+2)(x-2)-(x-2)$

= $(x-2)*[(x^2+2x+4)+6(x+2)-1]$

= $(x-2)*(x^2+8x+15)$

= $(x-2)(x+3)(x+5)$

How do you factor x^3+6x^2-x-30x^3+6x^2-x-30?