How do you factor #x^3+8#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Nghi N. Dec 17, 2015 #(x + 2)(x^2 - 2x + 4)# Explanation: Use the algebraic identity: #a^3 + b^3 = (a + b)(a^2 - ab + b^2)# #x^3 + 8 = (x + 2)(x^2 - 2x + 4)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1203 views around the world You can reuse this answer Creative Commons License