# How do you factor x^3+8?

$\left(x + 2\right) \left({x}^{2} - 2 x + 4\right)$
Use the algebraic identity: ${a}^{3} + {b}^{3} = \left(a + b\right) \left({a}^{2} - a b + {b}^{2}\right)$
${x}^{3} + 8 = \left(x + 2\right) \left({x}^{2} - 2 x + 4\right)$