How do you factor $x^3+8y^3$ ?

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Answer 1 · 2018-06-09T17:00:31

$(x + 2y)(x^2 – 2xy + 4y^2)$

This is a difference of cubes so use the formula:

$a^3 + b^3 = (a + b)(a^2 – ab + b^2)$

$x^3 + 8y^3 = (x + 2y)(x^2 – x2y + 2^2y^2)$

$= (x + 2y)(x^2 – 2xy + 4y^2)$

How do you factor x^3+8y^3x^3+8y^3?