How do you factor #x^3 - 9x^2 +27x - 27#?

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Answer 1 · 2018-07-02T16:36:59

#(x-3)^3#

#x^3-9x^2+27x-27#

=#x^3-27-9x^2+27x#

=#(x-3)(x^2+3x+9)-9x(x-3)#

=#(x-3)*(x^2+3x+9-9x)#

=#(x-3)*(x^2-6x+9)#

=#(x-3)*(x-3)^2#

=#(x-3)^3#