How do you factor #x^3+x^2x1#?
1 Answer
The result is
The reason is the following:
First, you apply Ruffini's Rule trying to divide the polynome by any of the divisors of the independent term; I tried to do it by (1) and it worked (remember that the sign of the divisor is changed when applying Ruffini's Rule):
 1 1 1 1

1  1 2 1
1 2 1 0
By doing this we have obtained that
And now it is easy to see that
(If you would not realise of that, you can always use the formula to solve seconddegree equations:
So, summarizing, the final result is: