# How do you factor (x^3)(x^6)+(8z^3)?

${a}^{3} + {b}^{3} = \left(a + b\right) \left({a}^{2} - a b + {b}^{2}\right)$
$\left({x}^{3}\right) \left({x}^{6}\right) + \left(8 {z}^{3}\right)$
$= {\left({x}^{3}\right)}^{3} + {\left(2 z\right)}^{3}$
$= \left({x}^{3} + 2 z\right) \left({x}^{6} - 2 {x}^{3} z + 4 {z}^{2}\right)$