How do you factor #x^4 + x^2 -6#?

1 Answer
May 10, 2015

#x^4 + x^2 - 6 = (x^2 - 2)(x^2 + 3)#

To find this, first let #y = x^2# to get the quadratic:
#y^2 + y - 6# and factor that.

Without plugging in the general quadratic solution, just notice that #y^2 + y - 6 = 0# for #y = 2#. So #(y - 2)# is one factor. The other factor is quickly seen to be #(y + 3)#.

Substituting #y = x^2# back in we get the final answer.