How do you factor #x^5 + 2x^4 - 3x^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer BRIAN M. Mar 23, 2016 #x^3(x+3)(x-1)# Explanation: To factor #x^5 + 2x^4 - 3x^3# completely begin by factoring out the common factor #x^3# #x^3(x^2+2x-3)# now factor the trinomial using #(3)(-1) = -3# #3-1 = 2# #(x+3)(x-1)# #x^3(x+3)(x-1)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1748 views around the world You can reuse this answer Creative Commons License