How do you factor #(x^5) - (x^4) + (x^3) - (x^2) - 12x + 12#?
The sum of the coefficients is zero, that is:
The remaining quartic factor is actually quadratic in
The first of these can be viewed as a difference of squares:
...using the difference of squares identity:
The remaining quadratic factor has no linear factors with real coefficients, since