How do you factor x^6 + 16x^3 + 64? Algebra Polynomials and Factoring Factoring Completely 1 Answer Konstantinos Michailidis Mar 12, 2016 We have that x^6 + 16x^3 + 64=(x^3)^2+2*8*x^3+(8)^2=(x^3+8)^2 But x^3+8 can be factored further as follows x^3+8=x^3+2^3=(x+2)*(x^2-2x+4) Finally we get x^6+16x^3+64=(x+2)^2*(x^2-2x+4)^2 Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-75 completely? How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? See all questions in Factoring Completely Impact of this question 7279 views around the world You can reuse this answer Creative Commons License