Question

How do you factor `x^6/8-y^3/27`?

Answer 1

Use the identity: a^3 - b^3 = (a - b) (a^2 + ab + b^2)

Let `x^2 = X,` then

`(X/2)^3 - (y/3)^3` = `(X - y)(X^2 + Xy + y^2)`=

= `(x^2 - y)(x^4 + x^2y + y^2)`