How do you factor #x^6-x^4-12x^2#?

1 Answer
May 25, 2015

Given #x^6-x^4-12x^2#

Step 1: extract the obvious common factor #x^2#
#= (x^2)(x^4-x^2-12)#

Step 2: simplify the second term by temporarily substituting #t=x^2#
#=(x^2)(t^2-t-12)#
#=(x^2)(t-4)(t+3)#

Step 3: re-insert #x^2# in place of #t#
#=(x^2)(x^2-4)(x^2+3)#

Step 4: factor the middle term as the difference of squares
#=(x^2)(x+2)(x-2)(x^2+3)#