# How do you factor x^9 - y^3z^5?

Feb 14, 2016

However, if the question were to factor ${x}^{9} - {y}^{3} {z}^{6}$, it could be factored as a difference of cubes:
${x}^{9} - {y}^{3} {z}^{6} = \left({x}^{3} - y {z}^{2}\right) \left({x}^{6} + {x}^{3} y {z}^{2} + {y}^{2} {z}^{4}\right)$