How do you factor #y^2-2y-63#?

1 Answer
Jun 1, 2016

Answer:

The factorization of #y^2-2y-63# is
#(y-9)(y+7)#

Explanation:

To find the factorization of #y^2-2y-63#

#ax^2 + bx + c #
Begin by listing the factors of the "c" term
The factors of 63 are
1 and 63
3 and 21
7 and 9

Next we look at the signs of the trinomial
The second sign is negative which means we are subtracting the factors to achieve the middle term.
Therefore the factors will have different signs and since the first term is negative the larger term will be negative.
#-9 + 7#

Now we form our binomials

#(x-9)(x+7)#