# How do you factor #y= 2x^2 - 5x -3 #?

##### 2 Answers

Dec 14, 2015

#### Answer:

Use the quadratic formula to find:

#y = 2x^2-5x-3 = (2x+1)(x-3)#

#### Explanation:

This quadratic is of the form

#x = (-b+-sqrt(b^2-4ac))/(2a) = (5+-sqrt(5^2-(4xx2xx-3)))/(2xx2)#

#=(5+-sqrt(49))/4 = (5+-7)/4#

That is

Hence our quadratic has linear factors

#y = 2x^2-5x-3 = (2x+1)(x-3)#

Dec 14, 2015

#### Answer:

Find a suitable split for the middle term, then factor by grouping to find:

#y = 2x^2-5x-3 =(2x+1)(x-3)#

#### Explanation:

Look for a pair of factors of

The pair

#y = 2x^2-5x-3#

#=2x^2-6x+x-3#

#=(2x^2-6x)+(x-3)#

#=2x(x-3)+1(x-3)#

#=(2x+1)(x-3)#