# How do you factor y = 2x^3+x-3?

It is $y = 2 {x}^{3} + x - 3 \implies y = 2 {x}^{3} + x - 2 - 1 \implies y = 2 \left({x}^{3} - 1\right) + \left(x - 1\right) \implies y = 2 \left(x - 1\right) \left({x}^{2} + x + 1\right) + \left(x - 1\right) \implies y = \left(x - 1\right) \cdot \left(2 {x}^{2} + 2 x + 3\right)$