# How do you factor y^3+27?

Jul 23, 2016

$\left(y + 3\right) \left({y}^{2} - 3 y + 9\right)$
This is the sum of two cubes. $\left({y}^{3} + 27\right)$
${y}^{3} + 27$
=$\left(y + 3\right) \left({y}^{2} - 3 y + 9\right)$