How do you factor y= 3x^7 - 9x ^6 + 18x ^5?
1 Answer
Dec 16, 2015
y = 3x^7-9x^6+18x^5=3x^5(x^2-3x+6)
Explanation:
First note that all the terms are divisible by
y = 3x^7-9x^6+18x^5=3x^5(x^2-3x+6)
The remaining quadratic factor is in the form
This has discriminant
Delta = b^2-4ac = (-3)^2-(4xx1xx6) = 9-24 = -15
Since this is negative, the quadratic has only Complex zeros and cannot be factored any further with Real coefficients.