# How do you factor #y^6 - 64z^8#?

##### 1 Answer

Feb 6, 2016

#### Explanation:

To solve this problem you must think what can i factor for the y^6

Since the rule of exponent is y^6

(y)^3 * (y^3) add them

so y^6

Think of it as y^2

(y) * (y) = y^2

To get 64

what is it divisible by?

Check if it is divisible by 2 to get perfect squares if not

2 * 2 = 4 until 8*8 = 64

So you got the second one.

The factor of z can be the same as above

which is (z^4) (z^4) and then you add them to the parenthesis.

In any order.