# How do you factor #y= 8m^2 - 41m - 42#?

##### 3 Answers

#### Answer:

Find a suitable splitting of the middle term, then factor by grouping to find:

#8m^2-41m-42=(8m+7)(m-6)#

#### Explanation:

Find a pair of factors of

The split of

That leads to the following possibilities to consider:

#16xx21#

#bb (48xx7)#

#112xx3#

#336xx1#

Having found the pair

#8m^2-41m-42#

#=8m^2-48m+7m-42#

#=(8m^2-48m)+(7m-42)#

#=8m(m-6)+7(m-6)#

#=(8m+7)(m-6)#

#### Answer:

#### Explanation:

You could look for values

(perhaps using the AC method)

...but unless you get lucky, there are quite a few factorings possible.

As an alternative you could use the quadratic formula:

The numbers involved are still ugly but if you use a calculator or spreadsheet (evaluating only the

you should get:

Therefore one of the factors will be:

Simple division (

gives the other term:

#### Answer:

Alternatively, complete the square to find:

#8m^2-41m-42 = (m-6)(8m+7)#

#### Explanation:

Alternatively, you can complete the square to proceed directly to the answer as follows:

#8m^2-41m-42#

#=8(m^2-41/8 m - 21/4)#

#=8(m^2-41/8 m + (41/16)^2 - (41/16)^2 - 21/4)#

#=8((m-41/16)^2 - 1681/256 - 1344/256)#

#=8((m-41/16)^2 - 3025/256)#

#=8((m-41/16)^2 - (55/16)^2)#

#=8((m-41/16) - 55/16)((m-41/16) + 55/16)#

#=8(m-96/16)(m+14/16)#

#=8(m-6)(m+7/8)#

#=(m-6)(8m+7)#

...using the difference of squares identity:

#a^2-b^2 = (a-b)(a+b)#

with

Ouch!