# How do you factorize (2x - 6) ( x + 1) ( x - 4) fully?

$= 2 \left(x - 3\right) \left(x + 1\right) \left(x - 4\right)$
$\left(2 x - 6\right) \left(x + 1\right) \left(x - 4\right)$
$= \left(2 \cdot x - 2 \cdot 3\right) \left(x + 1\right) \left(x - 4\right)$
$= 2 \left(x - 3\right) \left(x + 1\right) \left(x - 4\right)$