# How do you figure out a diagonal measurement of a rectangle if width is 14' and the height is 5'?

Apr 3, 2018

You use the Pythagorean Theorem (${a}^{2} + {b}^{2} = {c}^{2}$).

#### Explanation:

Given that the width is 14' and the height is 5', you can figure out that the diagonal measurement is sqrt(221 by plugging those values into the equation.

${a}^{2} + {b}^{2} = {c}^{2}$
${14}^{2} + {5}^{2} = {c}^{2}$
${14}^{2} + {5}^{2} = 221$
${c}^{2} = 221$

Then, you just cancel out the "squared" part of "${c}^{2}$" by taking the square root (sqrt ) out (because they are exact opposites, so they cancel each other out, kind of like addition and subtraction)

${c}^{2}$=221
sqrt(${c}^{2}$=$\sqrt{221}$
c=$\sqrt{221}$

so you end up with $\sqrt{221} '$ as the diagonal measurement of the rectangle since it can no longer be simplified.