# How do you find a positive number whose square is 12 more than the number itself?

Jan 25, 2016

Translate the problem into an equation, and solve to find that the number is $4$

#### Explanation:

Translate the problem into an equation:
${x}^{2} = x + 12$

${x}^{2} - x - 12 = 0$

Try factoring. If this does not work, we can use the quadratic formula:
$\left(x + 3\right) \left(x - 4\right) = 0$

$x = - 3$ or $x = 4$

Throw out the negative result:
$x = 4$